This Math Talk focuses on values meeting a constraint. It encourages students to think about using values in an equation and to rely on what they know about cost in context to mentally solve problems. The strategies elicited here will be helpful later in the lesson when students write and solve systems of linear equations in two variables.
Many students are likely to approach the task by multiplying pounds of raisins by 4 and pounds of walnuts by 8, and then see if the sum of the two products is 15. Some students may arrive at their conclusions by reasoning and estimating. For example, seeing that a pound of walnuts costs $8, students may simply reason that the first combination is not possible. Or they may reason that the last combination is impossible because at $4 a pound, 3.5 pounds of raisins would cost more than $12, so it is not possible to also get 1 pound of walnuts and pay only $15 total.
In describing their strategies, students need to be precise in their word choice and use of language (MP6).
Tell students to close their books or devices (or to keep them closed). Reveal one problem at a time. For each problem:
Keep all previous problems and work displayed throughout the talk.
Diego bought some raisins and walnuts to make trail mix.
Raisins cost $4 a pound and walnuts cost $8 a pound. Diego spent $15 on both ingredients.
Decide if each pair of values could be a combination of raisins and walnuts that Diego bought.
Ask students to share their strategies for each problem. Record and display their responses for all to see. To involve more students in the conversation, consider asking:
Conclude by reminding students that the given situation involves a cost constraint. Emphasize that only the third option, 2.25 pounds of raisins and 0.75 pounds of walnuts, satisfy the constraint. One way to check if certain values meet the constraint is by writing an equation and checking if it is true. For example, the equation 4(2.25)+8(0.75)=15 is true. If we replace the weights of raisins and walnuts with other pairs of values, the equation would be false.
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This Math Talk focuses on values meeting a constraint. It encourages students to think about using values in an equation and to rely on what they know about cost in context to mentally solve problems. The strategies elicited here will be helpful later in the lesson when students write and solve systems of linear equations in two variables.
Many students are likely to approach the task by multiplying pounds of raisins by 4 and pounds of walnuts by 8, and then see if the sum of the two products is 15. Some students may arrive at their conclusions by reasoning and estimating. For example, seeing that a pound of walnuts costs $8, students may simply reason that the first combination is not possible. Or they may reason that the last combination is impossible because at $4 a pound, 3.5 pounds of raisins would cost more than $12, so it is not possible to also get 1 pound of walnuts and pay only $15 total.
In describing their strategies, students need to be precise in their word choice and use of language (MP6).
Tell students to close their books or devices (or to keep them closed). Reveal one problem at a time. For each problem:
Keep all previous problems and work displayed throughout the talk.
Diego bought some raisins and walnuts to make trail mix.
Raisins cost $4 a pound and walnuts cost $8 a pound. Diego spent $15 on both ingredients.
Decide if each pair of values could be a combination of raisins and walnuts that Diego bought.
Ask students to share their strategies for each problem. Record and display their responses for all to see. To involve more students in the conversation, consider asking:
Conclude by reminding students that the given situation involves a cost constraint. Emphasize that only the third option, 2.25 pounds of raisins and 0.75 pounds of walnuts, satisfy the constraint. One way to check if certain values meet the constraint is by writing an equation and checking if it is true. For example, the equation 4(2.25)+8(0.75)=15 is true. If we replace the weights of raisins and walnuts with other pairs of values, the equation would be false.