Solving Systems by Substitution

10 min

Narrative

This activity uses pictures to set up the idea of solving systems by substitution. Students may be familiar with this type of problem in which a small detail change is important to solving the system. No such trick is given in this problem, but the idea can be addressed if students bring it up.

While several valid strategies exist, focus attention on solving for the value of each picture and using that value to find additional values for other pictures. This primes student thinking for using substitution to solve systems of linear equations.

Launch

Arrange students in groups of 2. Display the image for all to see. Give students 1 minute of quiet think time, then ask students if they have ever seen a similar type of problem outside of class. If it is unclear, tell students that they should try to find the numerical value of the last expression by using the information in the other equations. Give students 5–7 minutes to solve the problem with their partner, then follow with a whole-class discussion.

Student Task

Find the value of the last line. Be prepared to explain your reasoning.

system of equations using stars, suns, and rockets

Sample Response

6. Sample reasoning: The star is worth 3 because 3 of them add up to 9, and 93=3\frac{9}{3} = 3. The sun is worth 2 because 2 stars are worth 6, and the solution to 6x=46 - x = 4 is x=2x = 2. The rocket is worth 5 because we know the sun is worth 2, so 2 rockets must be worth 10, and 102=5\frac{10}{2} = 5. The last line is 6 because 32+5=63 - 2 + 5 = 6.

Activity Synthesis (Teacher Notes)

Ask a group to share their strategy to get started, and stop them when they offer the value of one of the symbols. Ask another group how they used that information to get the value of another symbol. Continue selecting groups until the value of each symbol is known and the value of the last line is shared.

If it does not come up in the discussion of the strategies, point out that the first three equations could be written as a system.

​​{3x=92xy=42z+y=12​​\begin{cases} 3x = 9 \\ 2x - y = 4 \\ 2z + y = 12 \end{cases}

The solution to this system is x=3,y=2,z=5x = 3, y = 2, z = 5 and can be found by solving each equation from the first to the third, using known information.
 

Standards
Building On
  • 8.EE.C·Analyze and solve linear equations and pairs of simultaneous linear equations.
  • 8.EE.C·Analyze and solve linear equations and pairs of simultaneous linear equations.
Building Toward
  • A-REI.6·Solve systems of linear equations exactly and approximately (e.g., with graphs), focusing on pairs of linear equations in two variables.
  • A-REI.6·Solve systems of linear equations exactly and approximately (e.g., with graphs), focusing on pairs of linear equations in two variables.
  • A-REI.6·Solve systems of linear equations exactly and approximately (e.g., with graphs), focusing on pairs of linear equations in two variables.
  • HSA-REI.C.6·Solve systems of linear equations exactly and approximately (e.g., with graphs), focusing on pairs of linear equations in two variables.

15 min

10 min