In this activity, students see a situation in which a percent change is applied twice, first on the initial amount, and then on the amount that results from the first percent change. The multiplicative way of expressing the change is particularly helpful in such a situation. The example uses a familiar context of sales and discounts. The repeated decay results from applying a factor that is less than 1 more than once.
All books at a bookstore are 25% off. Priya bought a book originally priced at $32. The cashier applied the storewide discount and then took another 25% off for a coupon that Priya brought. If there was no sales tax, how much did Priya pay for the book? Show your reasoning.
Priya paid $18. Sample reasoning: 32⋅(0.75)⋅(0.75)=18
Students may have chosen to calculate the price after each discount separately. For instance, they may have found the cost after the first discount to be $24 (because 32⋅(0.75)=24, or 32−(0.25)⋅32=24), and then calculated 24⋅(0.75), or 24−(0.25)⋅24. To help them see the repeated multiplication by a factor, consider recording their steps without evaluating any step.
Focus the discussion on different expressions that can be used to efficiently calculate the final cost of the book, for instance:
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In this activity, students see a situation in which a percent change is applied twice, first on the initial amount, and then on the amount that results from the first percent change. The multiplicative way of expressing the change is particularly helpful in such a situation. The example uses a familiar context of sales and discounts. The repeated decay results from applying a factor that is less than 1 more than once.
All books at a bookstore are 25% off. Priya bought a book originally priced at $32. The cashier applied the storewide discount and then took another 25% off for a coupon that Priya brought. If there was no sales tax, how much did Priya pay for the book? Show your reasoning.
Priya paid $18. Sample reasoning: 32⋅(0.75)⋅(0.75)=18
Students may have chosen to calculate the price after each discount separately. For instance, they may have found the cost after the first discount to be $24 (because 32⋅(0.75)=24, or 32−(0.25)⋅32=24), and then calculated 24⋅(0.75), or 24−(0.25)⋅24. To help them see the repeated multiplication by a factor, consider recording their steps without evaluating any step.
Focus the discussion on different expressions that can be used to efficiently calculate the final cost of the book, for instance: