Unit 7 Introduction To Quadratic Functions — Unit Plan

TitleAssessment
Lesson 1
A Different Kind of Change
100 Meters of Fencing

A rectangular yard is enclosed by 100 meters of fencing. The table shows some possible values for the length and width of the yard. 

length (meters) width (meters) area (square meters)
10 40 400
20 30
25 25 625
35 15 525
40
  1. Complete the table with the missing values.
  2. If the values for length and area are plotted, what would the graph look like?
  3. How is the relationship between the length and the area of the rectangle different from other kinds of relationships we’ve seen before?
Show Solution
  1. The missing value in the second row is 600. The missing values in the last row are 10 and 400.
  2. Sample response: The points would form a stretched out upside-down U shape, or an arch.
  3. Sample response: As one quantity increases, the other quantity first increases and then decreases, instead of always increasing or always decreasing.
Lesson 2
How Does It Change?
Comparing Types of Growth

Here are three patterns of dots.

Pattern A

<p>Four steps of a growing pattern. Step 0 is blank. Step 1: 2 dots, one atop the other. Step 2: 4 dots, 2 in row 1 and 2 in row 2. Step 3: 6 dots, 3 dots on row 1 and 3 dots on row 2.</p>

Pattern B

<p>Four steps of a growing pattern.</p>
Four steps of a growing pattern. Step 0: one  dot. Step 1: two dots in a row. Step 2: three dots on row 1, two dots above the last 2 dots on row 2. Step 3: four dots on row 1, 3 dots above the last 3 dots on row 2 and 3 dots above row 2 on row 3.

Pattern C

<p>Four steps of a growing pattern.</p>
Fours steps of a growing pattern. Step 0: one  dot. Step 1: three dots in a row. Step 2: three dots on row 1, three dots above on row 2, three dots above on row 3. Step 3: nine dots on row 1, nine dots above on row 2 and nine dots above on row 3.

Which pattern shows a quadratic relationship between the step number and the number of dots? Explain or show how you know.

Show Solution

Pattern B shows a quadratic relationship. Sample explanations:

  • The number of dots is the step number squared plus 1, or n2+1n^2+1.
  • (Students might answer by elimination.) Pattern A grows linearly. It is growing by 2 each time. Pattern C is growing by a factor of 3 each time, so it grows exponentially.
  • (Students might recall the pattern they saw in the lesson but not yet internalize the squared input.) Pattern B is growing by 1, then by 3, then by 5, which is the pattern we saw in other examples of quadratic relationships in the lesson.
Section A Check
Section A Checkpoint
Problem 1

Pattern of dots for steps 1 through 4

  1. Write an expression that shows the relationship between the step number, nn, and the number of dots.
  2. Is this relationship linear, exponential, or quadratic? Explain your reasoning.
Show Solution
  1. n21n^2-1
  2. It is quadratic because it has a squared term in the expression for the relationship.
Lesson 3
Building Quadratic Functions from Geometric Patterns
A Quadratic Function?

Here is a pattern of squares.

<p>Three steps of a growing pattern.</p>
Three steps of a growing pattern. Step 1: Total of two squares, stacked with the bottom square upper left corner attached to the upper square bottom right corner. Step 2: Total of six squares, two squares on row 1, two squares on row 2 and two squares on row 3. Row 2 and 3 form a two by two square, with the lower right corner attached to the upper left corner of row 1. Step 3: Total of twelve squares, three squares on row 1, row 2, row 3 and row 4. Row 2, 3 and 4 form a three by three square, with the lower right corner attached to the upper left corner of row 1.

  1. Write an equation to represent the relationship between the step number, nn, and the number of squares in the pattern. Briefly describe how each part of the equation relates to the pattern.
  2. Is the relationship between the step number and the number of squares a quadratic function? Explain how you know.
Show Solution
  1. y=n2+ny = n^2 + n (or equivalent), because there is an nn-by-nn array of small squares, which gives n2n^2, and then there is a row of nn squares in the lower right.
  2. The relationship is a quadratic function because the number of squares could be expressed as n2+nn^2+n, which is a quadratic expression.
Lesson 4
Comparing Quadratic and Exponential Functions
Comparing $5x^2$ and $2^x$

Tyler completes the table comparing values of the expressions 5x25x^2 and 2x2^x.

xx 5x25x^2 2x2^x
1 5 2
2 20 4
3 45 8
4 80 16

Tyler concludes that 5x25x^2 will always be greater than 2x2^x for the same value of xx. Do you agree? Explain or show your reasoning.

Show Solution

Tyler is not correct. For small values of xx, 5x25x^2 is greater than 2x2^x, but 2x2^x is eventually greater because it always doubles when xx increases by 1. When x=9x = 9, 5(9)2=4055(9)^2 = 405, and 29=5122^{9} = 512, so 2x2^x is larger.

Lesson 5
Building Quadratic Functions to Describe Situations (Part 1)
Where Will It Be?

The expression 16t216t^2 represents the distance in feet that an object falls after tt seconds. The object is dropped from a height of 906 feet.

  1. What is the height in feet of the object 2 seconds after it is dropped?
  2. Write an expression representing the height of the object in feet tt seconds after it is dropped.
Show Solution
  1. 842, or 90664906 - 64 (or equivalent) 
  2. 90616t2906-16t^2
Lesson 6
Building Quadratic Functions to Describe Situations (Part 2)
Rocket in the Air

The height, hh, of a stomp rocket (propelled by a short blast of air) above the ground after tt seconds is given by the equation h(t)=5+100t16t2h(t) = 5 + 100t - 16t^2. Here is a graph that represents hh.

<p>Graph of the quadratic function <span class="math"><span class="katex"><span class="katex-mathml"><math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>h</mi><mo stretchy="false">(</mo><mi>t</mi><mo stretchy="false">)</mo><mo>=</mo><mn>5</mn><mo>+</mo><mn>100</mn><mi>t</mi><mo>−</mo><mn>16</mn><msup><mi>t</mi><mn>2</mn></msup></mrow><annotation encoding="application/x-tex">h(t)=5+100t - 16t^2</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:1em;vertical-align:-0.25em;"></span><span class="mord mathnormal">h</span><span class="mopen">(</span><span class="mord mathnormal">t</span><span class="mclose">)</span><span class="mspace" style="margin-right:0.2778em;"></span><span class="mrel">=</span><span class="mspace" style="margin-right:0.2778em;"></span></span><span class="base"><span class="strut" style="height:0.7278em;vertical-align:-0.0833em;"></span><span class="mord">5</span><span class="mspace" style="margin-right:0.2222em;"></span><span class="mbin">+</span><span class="mspace" style="margin-right:0.2222em;"></span></span><span class="base"><span class="strut" style="height:0.7278em;vertical-align:-0.0833em;"></span><span class="mord">100</span><span class="mord mathnormal">t</span><span class="mspace" style="margin-right:0.2222em;"></span><span class="mbin">−</span><span class="mspace" style="margin-right:0.2222em;"></span></span><span class="base"><span class="strut" style="height:0.8141em;"></span><span class="mord">16</span><span class="mord"><span class="mord mathnormal">t</span><span class="msupsub"><span class="vlist-t"><span class="vlist-r"><span class="vlist" style="height:0.8141em;"><span style="top:-3.063em;margin-right:0.05em;"><span class="pstrut" style="height:2.7em;"></span><span class="sizing reset-size6 size3 mtight"><span class="mord mtight">2</span></span></span></span></span></span></span></span></span></span></span></span> on a coordinate plane, origin <span class="math"><span class="katex"><span class="katex-mathml"><math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>O</mi></mrow><annotation encoding="application/x-tex">O</annotation></semantics></math></span><span class="katex-html" aria-hidden="true"><span class="base"><span class="strut" style="height:0.6833em;"></span><span class="mord mathnormal" style="margin-right:0.02778em;">O</span></span></span></span></span>.</p>
Graph of the quadratic function h(t)=5+100t16t2h(t) = 5 + 100t - 16t^2on a coordinate plane, origin OO. Horizontal axis scale 0 to 7 by 1’s, labeled “time (seconds)”. Vertical axis scale 0 to 200 by  50’s, labeled “height above ground (feet)”. Some of the points are (0 comma 5), (1 comma 89), (2 comma 141), (3 comma 161) to a maximum near (3 point 125 comma 161 point 25), then decreasing through (4 comma 149), (5 comma 105), (6 comma 29) and (6.3 comma 0).

  1. How does the 5 in the equation relate to the graph?
  2. What does 100t100t in the equation mean in terms of the rocket?
  3. What does the -16t2\text{-}16t^2 mean in terms of the rocket?
  4. Estimate the time when the rocket hits the ground.
Show Solution
  1. The graph intersects the vertical axis at 5. 
  2. It indicates that the initial velocity of the rocket was 100 feet per second upward.
  3. This indicates the effect of gravity pulling the rocket back toward Earth.
  4. At about 6.3 seconds.
Lesson 7
Building Quadratic Functions to Describe Situations (Part 3)
Making the Greatest Revenue

This graph represents the revenue, rr, in dollars that a company expects if they sell their product for pp dollars.

<p>Graph of non linear function.</p>
Graph of non linear function, origin O. Horizontal axis, price, dollars, from 0 to 20 by 2’s. Vertical axis, revenue, dollars, 0 to 6000 by 1000’s. Line starts at 0 comma 0, increases until 10 comma 5000 then decreases until 20 comma 0. Passes through approximately 4 comma 3250 and 16 comma 3250.

  1. Based on this model, which price would generate more revenue for the company, $5 or $17? Explain how you know.
  2. At what price should the company sell their product if they wish to make as much revenue as possible? How much revenue will they make?
  3. What is an appropriate domain for the function? Explain how you know.
Show Solution
  1. $5, because it would generate about $3,700 in revenue. Charging $17 would bring in about $2,500.
  2. Based on the graph, a price of $10 would bring in about $5,000.
  3. 0p200 \leq p \leq 20, because the price has to be non-negative, and the company would earn negative revenue if the price were more than $20.
Section B Check
Section B Checkpoint
Problem 1

A pattern of squares grows based on the expression 10n210n^2, where nn represents the step of the pattern.

A pattern of dots grows based on the expression 3n3^n, where nn represents the step of the pattern.

Han says that even though he doesn’t know which step it happens on, he knows that after some step, there will always be more dots than squares after that step. Do you agree or disagree? Explain your reasoning.

Show Solution
I agree. Sample reasoning: The squares grow in a quadratic pattern, and the factor of growth between each step decreases (becomes closer and closer to 1) after each step. The dots grow based on an exponential pattern, and the factor of growth is always 3.
Problem 2

A fall festival's pumpkin launcher sends pumpkins into the air so that the pumpkin's height in meters above the ground is modeled by the equation h(t)=-5t2+100th(t) = \text{-}5t^2 + 100t with tt as the time in seconds after launch.

A graph comparing the height above the ground in meters and the time in seconds. The x intercepts of the graph are at x=0 and x=20.

  1. At what height above the ground was the pumpkin when it was launched?
  2. What does the 100t100t in the equation mean in terms of the pumpkin?
  3. About when does the pumpkin hit the ground?
Show Solution
  1. 0 meters
  2. It means that the pumpkin was initially launched at 100 meters per second.
  3. 20 seconds after the launch
Lesson 8
Equivalent Quadratic Expressions
Writing Equivalent Expressions
  1. Use a diagram to show that (3x+1)(x+2)(3x +1)(x+2) is equivalent to 3x2+7x+23x^2 + 7x+2.
  2. Is (x+4)2(x+4)^2 equivalent to 2x2+8x+82x^2 + 8x + 8? Explain or show your reasoning.
Show Solution
  1. Diagram should show partial products of 3x(x)3x(x), 6x6x, xx, and 2, which add up to 3x2+7x+23x^2 + 7x+2.
  2. No. (x+4)(x+4)=x2+4x+4x+16=x2+8x+16(x+4)(x+4) = x^2 + 4x + 4x + 16 = x^2 + 8x + 16. (Students may use a diagram or distributive property to reason.)
Lesson 9
Standard Form and Factored Form
From One Form to Another

For each expression, write an equivalent expression in standard form. Show your reasoning.

  1. (2x+5)(x+1)(2x+5)(x+1)
  2. (x2)(x+2)(x-2)(x+2)
Show Solution
  1. 2x2+7x+52x^2 + 7x + 5. Sample reasoning: The diagram shows that (2x+5)(x+1)=2xx+2x1+5x+51(2x+5)(x+1) = 2x \boldcdot x + 2x \boldcdot 1 + 5 \boldcdot x + 5\boldcdot 1. Adding this together gives 2x2+7x+52x^2 + 7x + 5 in standard form.
    2x2x 55
    xx 2x22x^2 5x5x
    11 2x2x 55
  2. x24x^2 - 4. Sample reasoning: (x+2)(x2)=x2+(-2x)+2x+(-4)=x24(x+2)(x-2) = x^2 + (\text-2x) +2x + (\text-4) = x^2 - 4. The diagram also shows that (x+2)(x2)=x24(x+2)(x-2) = x^2-4.
    xx 22
    xx x2x^2 2x2x
    -2\text-2 -2x\text-2x -4\text-4
Section C Check
Section C Checkpoint
Problem 1

Write each equation in standard form, then identify the xx- and yy-intercepts in the graph of each.

  1. y=(x+1)(x1)y = (x+1)(x-1)
  2. y=(1x)(x+3)y = (1-x)(x+3)
Show Solution
  1. y=x21y = x^2 - 1. xx-intercepts: (-1,0),(1,0)(\text{-}1,0), (1,0). yy-intercept: (0,-1)(0,\text{-}1)
  2. y=-x22x+3y = \text{-}x^2 -2x+3. xx-intercepts: (1,0),(-3,0)(1,0), (\text{-}3,0). yy-intercept: (0,3)(0,3)
Lesson 11
Graphing from the Factored Form
Sketching a Graph

Function ff is given by f(x)=(x2)(x+4)f(x) = (x-2)(x+4). Without using graphing technology, answer the following questions.

  1. What are the xx-intercepts of the graph representing ff?
  2. What are the xx- and yy-coordinates of the vertex of the graph?
  3. What is the yy-intercept?
  4. Sketch a graph that represents ff.
    <p><strong>Blank x y coordinate plane with grid, and origin labeled “O”. There are 6 evenly-spaced horizontal and vertical gridlines to either side of the axes.</strong></p>
Show Solution
  1. (2,0)(2,0) and (-4,0)(\text-4,0)
  2. x=-1x = \text-1, y=(-12)(-1+4)=-9y = (\text-1-2)(\text-1+4) = \text-9
  3. yy-intercept is (0,-8)(0,\text-8), because (02)(0+4)=-8(0-2)(0+4) = \text-8.
  4. The graph opens upward with vertex at (-1,-9)(\text-1, \text-9) and xx-intercepts at (2,0)(2,0) and (-4,0)(\text-4,0).
    <p>Graph on coordinate plane.</p>
Lesson 12
Graphing the Standard Form (Part 1)
Matching Equations and Graphs

Here are graphs that represent three quadratic functions, defined by:

f(x)=x24g(x)=1x2h(x)=x2+4\displaystyle f(x) = x^2 - 4\\ g(x) = 1 -x^2\\ h(x)=x^2+4

<p>Coordinate plane with 3 quadratic functions. Curve A opens up and has minimum at 0 comma 4. Curve B opens up and has minimum at negative 4 comma 0. Curve C opens down and has maximum 0 comma 1.</p>

  1. Match each equation to a graph that represents it. Explain how you know.
  2. Write down the equation that can be represented by Graph C. Which part of the equation tells us that the graph opens downward?
Show Solution
  1. Sample response:
    • Graph A represents hh because the yy-intercept is (0,4)(0,4), and there are no xx-intercepts because this function always takes positive values.
    • Graph B represents ff because the yy-intercept is (0,-4)(0,\text-4), and the graph opens upward.
    • Graph C represents gg because the yy-intercept is (0,1)(0,1), and the graph opens downward.
  2. y=1x2y=1 - x^2. The negative coefficient of x2x^2 makes the graph open downward.
Lesson 13
Graphing the Standard Form (Part 2)
Sketching Graphs
  1. Consider the quadratic equation y=x24xy = x^2-4x. If we graph the equation, where are the xx-intercepts located? What is the xx-coordinate of the vertex?
  2. Here is a graph of y=x2y=x^2. Sketch a graph of y=x2+5xy = x^2 + 5x on the same graph. Briefly explain how you know where to sketch the graph.
    <p>Graph of Parabola y = x squared </p>
Show Solution
  1. The xx-intercepts are at x=0x = 0 and x=4x = 4, with the vertex halfway between the intercepts, at x=2x = 2.
  2. Sample reasoning: x2+5xx^2+5x is equivalent to x(x+5)x(x+5), so the xx-intercepts are at x=0x=0 and x=-5x=\text-5. The squared term has a positive coefficient so the graph opens upward. Adding a positive linear term to x2x^2 shifts the graph down and to the left.

<p>Graph of 2 parabolas  </p>

Lesson 14
Graphs That Represent Situations
Beach Ball Trajectory

The equation y=(-16t2)(t1)y=(\text-16t-2)(t-1) represents the height, in feet, of a beach ball thrown by a child, as a function of time, tt seconds after the ball is thrown.

  1. Find the zeros of the function. Explain or show your reasoning.
  2. What do the zeros tell us in this situation? Are both zeros meaningful?
  3. From what height is the beach ball thrown? Explain or show your reasoning.
Show Solution
  1. 1 and -18\text- \frac18. Sample reasoning:
    • From the factored form, we can tell that the graph intersects the horizontal axis at t=1t=1 and t=-18t=\text-\frac18. The zeros of the function are those same values.
    • (If students graph the function) The graph shows tt-intercepts at (-18,0)(\text- \frac18,0) and (1,0)(1,0).
  2. The zeros mean the time in seconds when the ball hits the ground. Only one of them is meaningful. The negative zero doesn’t mean anything here.
  3. From a height of 2 feet. Sample reasoning:
    • The height when t=0t=0 is (-16(0)2)(01)=(-2)(-1)=2(\text-16(0)-2)(0-1) = (\text-2)(\text-1) = 2.
    • (If students graph the function) The graph shows a yy-intercept of (0,2)(0,2).
Lesson 15
Vertex Form
Visualizing A Graph

Function ff is given by f(x)=(x+3)21f(x) = (x+3)^2 -1.

  1. Write the coordinates of the vertex of the graph of ff.
  2. Does the graph open upward or downward? Explain how you know.
Show Solution
  1. The vertex of ff is at (-3,-1)(\text-3,\text-1).
  2. The graph opens upward. The squared term has a positive coefficient (1).

Lesson 17
Changing the Vertex
Nudging a Graph
  1. Here is a graph that represents y=x2y = x^2. On the same coordinate plane, sketch a graph that represents y=(x6)2+10y = (x-6)^2 + 10.

    <p>Parabola in x y plane, origin O. X axis negative 6 to 6, by 2’s. Y axis negative 30 to 30, by 10s. Parabola opens upward with vertex at the origin.</p>

  2. The graph representing y=x2y = x^2 is shifted 2 units to the left, 10 units down, and flipped so that it opens downward, as shown. Write an equation that defines this curve.
    <p>Two parabolas in x y plane, origin O.</p>
    Two parabolas in x y plane, origin O. X axis negative 6 to 6, by 2’s. Y axis negative 30 to 30, by 10s. First parabola opens upward with vertex at the origin. Second parabola opens downward with vertex at negative 2 comma negative 10.
Show Solution
  1. A graph the same shape as y=x2y = x^2 but shifted 6 units to the right and 10 units up. Its vertex is at (6,10)(6,10).
  2. y=-(x+2)210y = \text-(x+2)^2-10
Section D Check
Section D Checkpoint
Problem 1

For each pair of functions, describe how the graphs are different.

  1. f(x)=x2+3f(x) = x^2 + 3 and g(x)=-x2+3g(x) = \text{-}x^2 +3
  2. h(x)=x2+6h(x) = x^2 + 6 and j(x)=x2+1j(x) = x^2 + 1
  3. m(x)=x2+1m(x) = x^2 + 1 and p(x)=(x2)2+1p(x) = (x-2)^2 + 1
  4. r(x)=x2r(x) = x^2 and s(x)=2x2s(x) = 2x^2
Show Solution
Sample responses:
  1. The graph of gg has the same shape as the graph of ff, but is flipped to open downward.
  2. The graph of jj has the same shape as the graph of hh, but is shifted 5 units down.
  3. The graph of pp has the same shape as the graph of mm, but the graph of pp is 2 units to the right.
  4. The graph of ss is taller and narrower than the graph of rr.
Problem 2

For each function, find the vertex, and then state whether it is a maximum or minimum.

  1. A(x)=-(x3)2+2A(x) = \text{-}(x-3)^2 + 2
  2. B(x)=2(x+1)2+3B(x) = 2(x+1)^2 + 3
  3. C(x)=-5(x+2)2C(x) = \text{-}5(x+2)^2
  4. D(x)=x28D(x) = x^2 - 8
Show Solution
  1. (3,2)(3,2) maximum
  2. (-1,3)(\text{-}1,3) minimum
  3. (-2,0)(\text{-}2,0) maximum
  4. (0,-8)(0,\text{-}8) minimum