Section C Section C Checkpoint

Problem 1

Select all expressions that are equivalent to $\frac{53}{100}$ .

\frac{3}{10} + \frac{5}{100}

\frac{50}{100} + \frac{3}{10}

\frac{5}{10} + \frac{3}{100}

\frac{1}{10} + \frac{4}{10} + \frac{3}{100}

\frac{31}{100} + \frac{12}{100} + \frac{1}{10}

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Solution

C, D, E

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Sample Response

C, D, E

Find the value of each expression. Explain or show your reasoning.

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Solution

$\frac{46}{100}$ . Sample response: I first added $\frac{19}{100}$ and $\frac{1}{100}$ to get $\frac{20}{100}$ , and then added $\frac{26}{100}$ .
$\frac{88}{100}$ . Sample response: I first added $\frac{4}{10}$ and $\frac{3}{10}$ to get $\frac{7}{10}$ , which is the same as $\frac{70}{100}$ , which I put together with $\frac{18}{100}$ .

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Sample Response

$\frac{46}{100}$ . Sample response: I first added $\frac{19}{100}$ and $\frac{1}{100}$ to get $\frac{20}{100}$ , and then added $\frac{26}{100}$ .
$\frac{88}{100}$ . Sample response: I first added $\frac{4}{10}$ and $\frac{3}{10}$ to get $\frac{7}{10}$ , which is the same as $\frac{70}{100}$ , which I put together with $\frac{18}{100}$ .

If we combine each person's times for the two races, who finished in less time? Explain or show your reasoning.

	Lin	Tyler
first race	$6\frac{5}{10}$ minutes	$6\frac{72}{100}$ minutes
second race	$6\frac{41}{100}$ minutes	$6\frac{26}{100}$ minutes

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Solution

Lin finished in less time. Her two times add to $12 \frac{91}{100}$ minutes and Tyler’s times add to $12 \frac{98}{100}$ minutes.

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Sample Response

Lin finished in less time. Her two times add to $12 \frac{91}{100}$ minutes and Tyler’s times add to $12 \frac{98}{100}$ minutes.