Section C Section C Checkpoint

Problem 1

Priya and her aunt wanted to see how far each could throw a disc. Priya’s aunt’s throw was 52 yards, which was 4 times the distance of Priya’s throw.

What was the distance of Priya’s throw in feet? Explain or show your reasoning.

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Solution

39 feet. Sample responses: 

  • Priya’s throw is 52÷452 \div 4 or 13 yards. One yard is 3 feet, so 13 yards is 13×313 \times 3 or 39 feet.
  • One yard is 3 feet, so 52 yards is 156 feet. This is 4 times Priya’s distance. I know 160=4×40160 = 4 \times 40 and 156 is 4 less than 160, so 156=4×39156 = 4 \times 39.
Show Sample Response
Sample Response

39 feet. Sample responses: 

  • Priya’s throw is 52÷452 \div 4 or 13 yards. One yard is 3 feet, so 13 yards is 13×313 \times 3 or 39 feet.
  • One yard is 3 feet, so 52 yards is 156 feet. This is 4 times Priya’s distance. I know 160=4×40160 = 4 \times 40 and 156 is 4 less than 160, so 156=4×39156 = 4 \times 39.

Problem 2

A rectangle has a width of 2142 \frac {1}{4} inches. The perimeter of the rectangle is 13 inches. What is the length of the rectangle? Explain or show your reasoning.

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Solution

4144\frac{1}{4} inches. Sample response: The two 2142\frac{1}{4}-inch sides make up 214+2142\frac{1}{4} + 2\frac{1}{4} or 4244\frac{2}{4} inches of the perimeter. The other two sides together are 1342413 - 4\frac{2}{4} or 8248\frac{2}{4} inches long. Each of those sides is 4144 \frac{1}{4} inches long because 2×414=8242 \times 4\frac{1}{4} = 8\frac{2}{4}.

Show Sample Response
Sample Response

4144\frac{1}{4} inches. Sample response: The two 2142\frac{1}{4}-inch sides make up 214+2142\frac{1}{4} + 2\frac{1}{4} or 4244\frac{2}{4} inches of the perimeter. The other two sides together are 1342413 - 4\frac{2}{4} or 8248\frac{2}{4} inches long. Each of those sides is 4144 \frac{1}{4} inches long because 2×414=8242 \times 4\frac{1}{4} = 8\frac{2}{4}.