Section B Practice Problems

Problem 1

Mai has a sheet of stickers with 23 rows and 8 stickers in each row.

  1. Does Mai have more or less than 100 stickers? Explain your reasoning.
  2. How many stickers does Mai have? Explain or show your reasoning.
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Solution

Sample responses:

  1. She has more than 100 because 5×20=1005 \times 20 = 100, so 8×208 \times 20 and 8×238 \times 23 must be more than 100.
  2. Mai has 184 stickers: 8×208 \times 20 is 160, 8×38 \times 3 is 24 and 160+24=184160 + 24 = 184.

Problem 2

Find the value of 7×647 \times 64. Use a diagram if it is helpful.

diagram, rectangle

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Solution

Sample response: 448. I partitioned the longer side of the diagram into 60 and 4 and then found 7×607 \times 60 and 7×47 \times 4. Then I added 420 and 28, which is 448.

diagram

Problem 3

  1. Use the diagram to find the value of 8×5738 \times 573.

    Diagram, rectangle partitioned vertically into 3 rectangles.
    Diagram, rectangle partitioned vertically into 3 rectangles. Left rectangle, vertical side, 8, horizontal side, 5 hundred. Middle rectangle, horizontal side, seventy. Right rectangle, horizontal side, 3.

  2. Find the value of 4×3,5164 \times 3,516.

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Solution
  1. 4,584. Sample response: 4,000+560+24=4,5844,000 + 560 + 24=4,584

    diagram

  2. 14,064. Sample response: 12,000+2,000+40+24=14,06412,000+2,000+40+24=14,064

    area diagram

Problem 4

  1. Use the diagram to find the value of 47×6247 \times 62.

    Diagram, rectangle partitioned vertically and horizontally into 4 rectangles.
    Diagram, rectangle partitioned vertically and horizontally into 4 rectangles. Top left rectangle, vertical side, 40, horizontal side, sixty. Top right rectangle, horizontal side, 5. Bottom 2 rectangles, vertical side, 7.

  2. Is this diagram helpful to finding the value of 47×6247 \times 62? Explain your reasoning.

    Diagram, rectangle partitioned vertically and horizontally into 4 rectangles.
    Diagram, rectangle partitioned vertically and horizontally into 4 rectangles. Top left rectangle, vertical side, 34, horizontal side, 48. Top right rectangle, horizontal side, 14. Bottom 2 rectangles, vertical side, 13.

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Solution
  1. 2,914, because 2,400+420+80+14=2,9142,400 + 420 + 80 + 14 = 2,914.
  2. Sample response: No, because the partial products I need to find here are difficult.

diagram

Problem 5

The diagram and calculations show two ways for finding the value of 2,518×62,518 \times 6.

Diagram, rectangle partitioned vertically into 4 rectangles.
Diagram, rectangle partitioned vertically into 4 rectangles. Left rectangle, vertical side, 6, horizontal side, 2 thousand. Left middle rectangle, horizontal side, 5 hundred. Right middle rectangle, horizontal side, 10. Right rectangle, horizontal side, 8.

multiply. 2 thousand 5 hundred 18 times 6.
multiply. 2 thousand 5 hundred 18 times 6. 7 rows. First row: 2 thousand 5 hundred 18. Second row: multiplication symbol, 6. Horizontal line. Third row: 48. Fourth row: 60. Fifth row: 3 thousand. Sixth row:  plus 12 thousand. Horizontal line. seventh row: 15 thousand 1 hundred 8

  1. How does each part of the vertical calculation relate to the diagram?
  2. Find the value of 3,172×53,172 \times 5 using a method of your choice.

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Solution
  1. Sample response: The 12,000 is 6×2,0006 \times 2,000, the 3,000 is 6×5006 \times 500, the 60 is 6×106 \times 10 and the 48 is 6×86 \times 8.
  2. 15,860. Sample response:

multiplication algorithm

Problem 6

Here is an incomplete calculation that uses partial products of 65×4365 \times 43.

  1. Write multiplication expressions that the numbers 15, 180, 200, and 2,400 each represent. Then find the value of 65×4365 \times 43.

    multiply. sixty 5 times 43.
    multiply. sixty 5 times 43. 6 rows. First row: sixty 5. Second row: multiplication symbol, 43. Horizontal line. Third row: 15. Fourth row: one hundred 80. Fifth row: two hundred. Sixth row: plus two thousand 4 hundred. Horizontal line.

  2. Find the value of the product 45×3845 \times 38.

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Solution
Sample responses:

a.
multiplication algorithm.

b.
multiplication algorithm

Problem 7

Here is how Elena calculates the value of 723×3723 \times 3.

multiply. 7 hundred 23 times 3, equals 2 thousand 1 hundred sixty 9.

  1. Where does the 9 in Elena's calculation come from? What about the 6?
  2. Where do the 2 and the 1 in calculation come from?
  3. Use Elena's method to find the value of 534×2534 \times 2.
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Solution
  1. Sample response: The 9 is from 3×33 \times 3 and the 6 represents 60, which is 3×203 \times 20.
  2. The 2 and 1 represent 2,100 and this is 3×7003 \times 700.
  3. 1,068. Sample response:

multiplication algorithm.

Problem 8

There are 4,218 students in school district A. School district B has 3 times as many students as school district A. How many students are in school district B? Explain or show your reasoning.

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Solution

12,654. Sample response:

multiplication algorithm

Problem 9

Clare checks her answers for some products. Without doing the computation again, she knows that these answers are incorrect. How might Clare have known?

  1. 5×5,783=27,9145 \times 5,783 = 27,914
  2. 7×8,419=54,2537 \times 8,419= 54,253
  3. 9×9,999=99,9999 \times 9,999= 99,999

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Solution

Sample responses:

  1. The value of the product is a multiple of 5, so the last digit will always be a 0 or a 5, never a 4.
  2. 7×8,000=56,0007 \times 8,000 = 56,000 so the answer is too small.
  3. The answer is too large because 9×10,0009 \times 10,000 is only 90,000.

Problem 10

Here is Mai's strategy to find the value of 9×8,2359 \times 8,235.

  1. Explain why Mai's method works.
  2. Use Mai's method to find the value of 9×6,7899 \times 6,789.
  3. Find the value of 9×6,7899 \times 6,789 using a strategy you learned. How is Mai's method like yours? How is it different?
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Solution

Sample responses:

  1. 9=1019 = 10 - 1, so Mai found 9×8,2359 \times 8,235 by finding 10×8,23510 \times 8,235 and then subtracting 1×8,2351 \times 8,235.
  2. subtraction algorithm

  3.  
    multiplication algorithm

    Alike: Both methods use multiplication and then another operation.

    Different: Mai's method involves using multiples of 6,789 that are easy to find and subtracting one from the other. My method involves multiplying the value of each digit in 6,789 by 9 and then adding the partial products.