Section A Practice Problems

Problem 1

Han says that the value of the 7 in 735,208 is 10 times the value of the 7 in 137,342. Do you agree with Han? Explain or show your reasoning.

Show Solution
Solution
No. Sample response: The 7 in 735,208 represents 700,000 and that is 100 times the value of 7,000, which is the value of 7 in 137,342.

Problem 2

Find the value of each product. Explain or show your reasoning.

  1. 27×5327 \times 53
  2. 518×6518 \times 6
Show Solution
Solution
  1. 1,431. Sample response:

    diagram

    The value of the product is 1,431 since 1,000+350+60+21=1,4311,000+350+60+21=1,431.

  2. 3,108. Sample response:

    diagram

     The value of the product is 3,108 since 3,000+60+48=3,1083,000 + 60 + 48 = 3,108.

Problem 3

Find the value of 7,518÷67,518 \div 6. Explain or show your reasoning.

Show Solution
Solution

1,253. Sample response: 

1,000×6=6,0001,000 \times 6 = 6,000
200×6=1,200200 \times 6 = 1,200
50×6=30050 \times 6 = 300
3×6=183 \times 6 = 181,000+200+50+3=1,2531,000 +200 + 50 + 3=1,253

Problem 4

What is the volume of this rectangular prism? Explain or show your reasoning.

Rectangular prism. 40 by sixty by eighty centimeters. 

Show Solution
Solution
192,000 cubic centimeters. Sample response: 40×60×80=192,00040 \times 60 \times 80 = 192,000

Problem 5

2 diagrams of equal length. 5 equal parts, 1 part shaded. Total length, 1.

  1. How does the drawing show 2÷52 \div 5? Explain or show your reasoning.
  2. How does the drawing show 25\frac{2}{5}? Explain or show your reasoning.
Show Solution
Solution

Sample responses:

  1. There are 2 wholes total and 1 out of 5 equal parts is shaded in each, so that's 2÷52 \div 5.
  2. Each shaded part is 1 of 5 equal parts in a whole or 15\frac{1}{5} so that's 25\frac{2}{5}.

Problem 6

Find the value of each product. Explain or show your reasoning.

  1. 100×50100 \times 50
  2. 120×50120 \times 50
  3. 127×50127 \times 50
Show Solution
Solution
  1. 5,000. Sample response: I just put 2 zeros on 50.
  2. 6,000. Sample response: I added 20 more 50s to 100×50100 \times 50, and that was 1,000 more.
  3. 6,350. Sample response: I added 7 more 50s to 120×50120 \times 50, and that was 350 more.

Problem 7

Complete the diagrams. Use each diagram to find the value of 253×31253 \times 31.

A
Diagram, rectangle partitioned vertically and horizontally into 6 rectangles. 
Diagram, rectangle partitioned vertically and horizontally into 6 rectangles. Top left rectangle, vertical side, 30, horizontal side, two hundred. Top middle rectangle, horizontal side, fifty. Top right rectangle, horizontal side, 3. Bottom 3 rectangles, vertical side, 1.

B
Diagram, rectangle partitioned horizontally into 2 rectangles. Top rectangle, vertical side, 30, horizontal side, two hundred fifty three. Bottom rectangle, vertical side, 1.

How are the strategies alike? How are they different?

Show Solution
Solution

7,843. Sample responses:

A
diagram
 

I added up all of the numbers to get 7,843.

B
diagram
 

I added up the numbers and got 7,843.

With the first strategy, I had more products to find and they were simpler, but then there were more products to add at the end. With the second strategy, there were fewer products to find but they were harder.

Problem 8

Find the value of 315×43315 \times 43, using partial products.

Show Solution
Solution

13,545. Sample response:

multiplication algorithm

Problem 9

Find the value of 16,452×616,452 \times 6. Use the standard algorithm.

Show Solution
Solution

98,712. Sample response:

multiplication algorithm

Problem 10

Find the value of 322×41322 \times 41. Use the standard algorithm.

Show Solution
Solution

13,202. Sample response:

multiplication algorithm

Problem 11

Find the value of 562×34562 \times 34. Use the standard algorithm.

Show Solution
Solution

19,108. Sample response:

multiplication algorithm

Problem 12

Andre is playing Greatest Product. He says the greatest product to make in the game is 987×65987 \times 65. Do you agree? Explain or show your reasoning.

Show Solution
Solution

Sample responses:

  • No. I calculated the product 987×65987 \times 65 and got 64,155. I think if I put the biggest digit in the greatest place value of the bigger number, and then put the second-biggest digit in the greater place value of the other number, I will get a greater product.

    multiplication algorithm

  • No. I can use the same numbers to get a bigger number. For example 976×85976 \times 85 is more than 80,000 while 987×65987 \times 65 is less than 70,000.

Problem 13

Use the digits 1, 2, 3, 4, and 5 to make a product with a value close to 8,000.

Show Solution
Solution

Sample response: 

multiplication algorithm

Problem 14

The recommended side lengths for a birdhouse for a yellow-bellied sapsucker are 13 centimeters by 13 centimeters for the floor and a height of from 31 centimeters to 38 centimeters. What are the least and greatest volumes for this birdhouse? Explain or show your reasoning.

Show Solution
Solution

5,239 cubic centimeters and 6,422 cubic centimeters. Sample responses:

The area of the floor is 13×1313 \times 13, which is 169 square centimeters. The smallest birdhouse is 169×31169 \times 31 cubic centimeters and the biggest birdhouse is 169×38169 \times 38 cubic centimeters. 

multiplication algorithm

multiplication algorithm

Problem 15

Jada remembers that the partial-products algorithm can go from left to right or from right to left. She wonders if the standard algorithm also can go in either direction.

  1. Calculate 418×53418 \times 53, using partial products right to left and left to right.
  2. Calculate 418×53418 \times 53, with the standard algorithm. What happens if you try to make the calculation from left to right?
Show Solution
Solution
  1. 22,154. Sample response:

    multiplication algorithm

    multiplication algorithm

  2. Sample response:

    multiplication algorithm

    I can multiply 50 by 400 and get 20,000 and record the 2 and the 0. But when I get to 50×1050 \times 10, if I record the 5 in the hundreds place, then I have to change it to 9 when I get to 50×850 \times 8, which is 4 hundred more. I have the same problem when I multiply 418 by 3 since 3×10=303 \times 10 = 30, but there are 2 more tens coming from 3×83 \times 8.

Problem 16

Clare has a strategy for multiplying a number by 99. To find 648×99648 \times 99, she calculates 648×100648 \times 100 and then subtracts 648648.

  1. Use Clare's strategy to calculate 648×99648 \times 99.
  2. Use the standard algorithm to calculate 648×99648 \times 99.
  3. Which strategy do you prefer? Explain your reasoning.
Show Solution
Solution
  1. 64,152. Sample response: 648×100=64,800648 \times 100 = 64,800 and 64,800648=64,15264,800 - 648 = 64,152
  2. 64,152. Sample response:

    multiplication algorithm

  3. Sample response: I liked Clare's method because I could do most of the math in my head. There was a lot of composing, with the standard multiplication algorithm. A nice thing about the standard algorithm was that I could use my answer, 5,832, for 9×6489 \times 648 to find 90×64890 \times 648, so I did not have to recalculate this.