Grade 6

End-of-Unit Assessment

End-of-Unit Assessment
1.

Priya ran 1121\frac12 miles today, and Tyler ran 3343\frac34 miles. How many times the length of Priya’s run was Tyler’s run?

A.

458\frac{45}{8} times as far

B.

94\frac{9}{4} times as far

C.

52\frac{5}{2} times as far

D.

25\frac{2}{5} times as far

Answer:

C

Teaching Notes

Students who select choice A have multiplied the lengths of the two runs together. Students who select choice B have answered the question, “How many miles longer was Tyler’s run?” Students who select choice D have reversed the order of division.

2.

Diego has run 3133\frac{1}{3} kilometers, which is 56\frac{5}{6} of the distance in a race. How long is the whole race?

Write a multiplication equation or a division equation to represent the question, and then find the answer.

Answer:

Sample response: 56?=313\frac{5}{6} \boldcdot {?} = 3\frac{1}{3}, or 313÷56=?3\frac{1}{3} \div \frac{5}{6} = {?}

The whole race is 4 kilometers, because 103÷56=10365=6015=4\frac{10}{3} \div \frac{5}{6} = \frac {10}{3} \boldcdot \frac{6}{5} = \frac{60}{15} = 4.

Teaching Notes

Students can reason about the length of the entire race by dividing (313÷56=?3\frac{1}{3} \div \frac{5}{6} = {?}) or by thinking about a unknown factor (56?=313\frac{5}{6} \boldcdot {?}= 3\frac{1}{3}). Some students may find the answer by reasoning indirectly (and independently of the equation they write to represent the question). For example, they may calculate 313÷53\frac{1}{3} \div 5 to find 16\frac{1}{6} of the distance in the race and then multiply the result (23\frac{2}{3}) by 6 to find the distance of the whole race.

3.
Select all statements that show correct reasoning for finding 12÷3812 \div \frac{3}{8}?
A.
Multiply 12 by 8, then divide by 3.
B.
Multiply 12 by 3, then divide by 8.
C.
Multiply 38\frac{3}{8} by 1, then multiply by 112\frac{1}{12}.
D.
Multiply 12 by 18\frac{1}{8}, then multiply by 3.
E.
Multiply 12 by 13\frac{1}{3}, then multiply by 8.

Answer: A, E

Teaching Notes
Students who select choice B or D have picked a statement that is equivalent to "Multiply by 38\frac{3}{8}" instead of "Multiply by 83\frac{8}{3}," Students who select choice C have reversed the dividend and divisor, picking a way to find 38÷12\frac{3}{8} \div 12 instead of 12÷3812 \div \frac{3}{8}.
4.

Divide.

  1. 23÷14\frac{2}{3} \div \frac{1}{4}
  2. 103÷26\frac{10}{3} \div \frac{2}{6}
  3. 56÷712\frac{5}{6} \div \frac{7}{12}
  4. 234÷432\frac{3}{4} \div \frac{4}{3}

Answer:

  1. 83\frac{8}{3} (or equivalent)
  2. 606\frac{60}{6} (or equivalent)
  3. 6042\frac{60}{42} (or equivalent)
  4. 3316\frac{33}{16} (or equivalent)

Teaching Notes

Students apply the algorithm for dividing fractions.

5.

Lin draws this tape diagram for 4÷344 \div \frac34:

Lin says that 4÷34=5144 \div \frac34 = 5\frac14 because there are 5 groups of 34\frac34 with 14\frac14 left over. Do you agree with Lin? Explain or show your reasoning.

Answer:

Sample response: No, I disagree. There are 5 groups of 34\frac34 in 3343\frac34. Then there is 14\frac14 left, and this makes 13\frac13 of another group. There are 5135\frac13 groups of 34\frac34 in 4.

Minimal Tier 1 response:

  • Work is complete and correct.
  • Sample: No, because 4÷34=5134 \div \frac34 = 5\frac13, not 5145\frac14.

Tier 2 response:

  • Work shows general conceptual understanding and mastery, with some errors.
  • Sample errors: Disagreement with Lin, but a minor error in logic or calculation leads to a different result other than 5135\frac13; agreement with Lin, with a reasonable but flawed argument.

Tier 3 response:

  • Significant errors in work demonstrate lack of conceptual understanding or mastery.
  • Sample errors: Disagreement with Lin based on a major flaw in logic or calculation; agreement with Lin with a badly flawed argument; agreement or disagreement without any stated justification.

Teaching Notes

Students who agree with Lin’s statement may have a fundamental misunderstanding of division that may come from working with remainders of whole number division.

6.

A box has a width of 2142\frac{1}{4} inches, a length of 2122\frac{1}{2} inches, and a height of 1341\frac{3}{4} inches.

How many 14\frac{1}{4}-inch cubes does it take to fill the box?

Answer:

630 cubes (9 cubes fit along the width of the box, 10 cubes fit along the length, and 7 cubes fit vertically.) 9107=6309 \boldcdot 10 \boldcdot 7 = 630

Teaching Notes

Students will need to use fraction division to calculate how many cubes will fit along each side of the box. Rather than using the standard algorithm, some students may visualize or otherwise reason conceptually about how many cubes with side length 14\frac14 inch it will take to reach a length of 2142\frac14 inches, etc.

7.

Elena has two aquariums, each shaped like a rectangular prism. For each question, explain or show your reasoning.

  1. One aquarium has a length of 72\frac72 feet, a width of 43\frac43 feet, and a height of 32\frac32 feet. What is the volume of the aquarium?
  2. Elena paints the entire back side of the second aquarium, which has a height of 1341\frac{3}{4} feet. The painted area is 5565\frac{5}{6} square feet. What is its length?

Answer:

  1. 7 cubic feet (or equivalent). The volume is the product of the aquarium's length, width, and height:  724332=7\frac72 \boldcdot \frac43 \boldcdot \frac32 = 7.

  2. 3133\frac13 feet (or equivalent). The length is the solution to 134=556\ell \boldcdot 1\frac34 = 5\frac56. By writing each mixed number as a fraction, the problem is made simpler: 74=356\frac74 \ell = \frac{35}{6}. Then =103\ell = \frac{10}{3}.

Minimal Tier 1 response:

  • Work is complete and correct, with complete explanation or justification.
  • Sample:
  • 7 cubic feet, because 724332=7\frac72 \boldcdot \frac43 \boldcdot \frac32 = 7.
  • 103\frac{10}{3} feet, because 556÷134=1035\frac56 \div 1\frac34 = \frac{10}{3}.

Tier 2 response:

  • Work shows good conceptual understanding and mastery, with either minor errors or correct work with insufficient explanation or justification.
  • Sample errors: Correct answers without justification; one or two errors in calculation, such as incorrect rewriting of mixed numbers, but correct equations or representations used.

Tier 3 response:

  • Work shows a developing but incomplete conceptual understanding, with significant errors.
  • Sample errors: One incorrect answer with invalid work or no work shown; any incorrect choice of multiplication or division; invalid method used to multiply or divide fractions or mixed numbers; more than two errors in calculation.

Tier 4 response:

  • Work includes major errors or omissions that demonstrate a lack of conceptual understanding and mastery.
  • Sample errors: Two incorrect answers with invalid work or no work shown; consistently incorrect choices of multiplication or division; repeated use of invalid methods to multiply or divide.

Teaching Notes

While most students should understand the context of the problem, some may still have difficulty understanding without a diagram. The second problem is about area, even though the aquarium is described as a rectangular prism.