Section B Section B Checkpoint

Problem 1

Lin measured the diameter and circumference of a circle. Then she used her measurements to calculate the area.

Han measured the diameter and circumference of a different circle.

diameter (in) circumference (in) area (in2)
Lin’s circle 6 19 28.5
Han’s circle 3 9.5 ?

Han thinks the area of his circle is 14.25 in2. Do you agree? Explain or show your reasoning.

Show Solution
Solution

Sample responses:

  • No, the area of a circle is not proportional to the diameter. Since the diameter of Han’s circle is one-half the diameter of Lin’s circle, the area of Han’s circle will be (12)2(\frac12)^2 the area of Lin’s circle.
  • No, the area of Han’s circle is about 7 in2. Possible strategies:
    • The radius is 1.5 inches because 3÷2=1.53 \div 2 = 1.5.
      Area=12circumferenceradius\text{Area} = \frac12 \text{circumference} \boldcdot \text{radius}
      Area=12(9.5)(1.5)\text{Area} = \frac12 (9.5) \boldcdot (1.5)
      Area=7.125\text{Area} = 7.125
    • The radius is 1.5 inches because 3÷2=1.53 \div 2 = 1.5.
      A=πr2A = \pi r^2
      A=3.14(1.5)2A = 3.14 * (1.5)^2
      A=7.065A = 7.065
Show Sample Response
Sample Response

Sample responses:

  • No, the area of a circle is not proportional to the diameter. Since the diameter of Han’s circle is one-half the diameter of Lin’s circle, the area of Han’s circle will be (12)2(\frac12)^2 the area of Lin’s circle.
  • No, the area of Han’s circle is about 7 in2. Possible strategies:
    • The radius is 1.5 inches because 3÷2=1.53 \div 2 = 1.5.
      Area=12circumferenceradius\text{Area} = \frac12 \text{circumference} \boldcdot \text{radius}
      Area=12(9.5)(1.5)\text{Area} = \frac12 (9.5) \boldcdot (1.5)
      Area=7.125\text{Area} = 7.125
    • The radius is 1.5 inches because 3÷2=1.53 \div 2 = 1.5.
      A=πr2A = \pi r^2
      A=3.14(1.5)2A = 3.14 * (1.5)^2
      A=7.065A = 7.065

Problem 2

What is the area of the shaded region?

A
$3\pi$ square units
B
$9\pi$ square units
C
$12\pi$ square units
D
$36\pi$ square units
Show Solution
Solution
$9\pi$ square units
Show Sample Response
Sample Response
$9\pi$ square units