Unit 1 Rigid Transformations And Congruence — Unit Plan

TitleTakeawaysStudent SummaryAssessment
Lesson 2
Naming the Moves

Here are the moves we have learned about so far:

  • A translation slides a figure without turning it. Every point in the figure goes the same distance in the same direction. For example, Figure A was translated down and to the left, as shown by the arrows. Figure B is a translation of Figure A.
    Two figures, one labelled A, and its translation, labelled B.
  • A rotation turns a figure about a point, called the center of the rotation. Every point on the figure goes in a circle around the center and makes the same angle. The rotation can be clockwise, going in the same direction as the hands of a clock, or counterclockwise, going in the other direction. For example, Figure A was rotated 4545^\circ clockwise around its bottom vertex. Figure C is a rotation of Figure A.
    Two figures, one labelled A, and its rotation, labelled C.
  • A reflection places points on the opposite side of a reflection line. The mirror image is a backwards copy of the original figure. The reflection line shows where the mirror should stand. For example, Figure A was reflected across the dotted line. Figure D is a reflection of Figure A.
    Two figures, one labelled A, and its reflection, labelled D
Is It a Reflection? (1 problem)

What type of move takes Figure A to Figure B?

Two identical 4 sided figures labeled A and B share a common vertex. A dashed line labeled l slants downward and to the right and passes through the common vertex.

Explain your reasoning.

Show Solution

Sample responses:

  • The move is 1 rotation. If Figure A is turned around the point shared by Figures A and B, it can land on Figure B.
  • The move is 2 reflections. If Figure A is flipped over line \ell and then flipped over again so that the shared points and angle line up, then it can land on Figure B.
Lesson 4
Making the Moves

transformation is a translation, rotation, reflection, or dilation, or a combination of these. To distinguish an original figure from its image, points in the image are sometimes labeled with the same letters as the original figure, but with the symbol attached, as in AA’ (pronounced “A prime”).

  • A translation can be described by two points. If a translation moves point AA to point AA’, it moves the entire figure the same distance and direction as the distance and direction from AA to AA’. The distance and direction of a translation can be shown by an arrow.

    For example, here is a translation of quadrilateral ABCDABCD that moves AA to AA’.

    A quadrilateral A, B, C, D, and its translation to A prime, B prime, C prime, D prime.

  • A rotation can be described by an angle and a center. The direction of the angle can be clockwise or counterclockwise.

    For example, hexagon ABCDEFABCDEF is rotated 9090^\circ counterclockwise using center PP.

    A hexagon A, B, C, D, E, F, and its rotation 90 degrees bout a center, P, to hexagon A prime, B prime, C prime, D prime, E prime, F prime.

  • A reflection can be described by a line of reflection (the “mirror”). Each point is reflected directly across the line so that it is just as far from the mirror line, but is on the opposite side.

    For example, pentagon ABCDEABCDE is reflected across line mm.

    A pentagon A, B, C, D, E, and its reflection in a line m, to pentagon A prime, B prime, C prime, D prime, E prime.

When we do one or more moves in a row, we often call that a sequence of transformations. For example, a sequence of transformations taking Triangle A to Triangle C is to translate Triangle A 4 units to the right, then reflect over line \ell.

There may be more than one way to describe or perform a transformation that results in the same image. For example, another sequence of transformations that would take Triangle A to Triangle C would be to reflect over line \ell, then translate Triangle A​′ 4 units to the right.

What Does It Take? (1 problem)

Triangle A B C on a grid. Let (0 comma 0) be the bottom left corner. Then the coordinates of triangle A B C are A(7 comma 10), B(11 comma 9) and C(2 comma 3).

For each description of a transformation, identify what information is missing.

  1. Translate triangle ABCABC to the right.

  2. Rotate triangle ABCABC 9090^\circ around point CC.

  3. Reflect triangle ABCABC over a line.
     

Show Solution

Sample responses:

  1. Distancehow many units to the right
  2. Directionclockwise or counterclockwise
  3. A drawing or description of where the line is
Lesson 5
Coordinate Moves

We can use coordinates to describe points and find patterns in the coordinates of transformed points.

We can describe a translation by expressing it as a sequence of horizontal and vertical translations.

For example, segment ABAB is translated right 3 and down 2.

Quadrilateral on a coordinate plane.
Quadrilateral on a coordinate plane. Horizontal axis scale negative 3 to 5 by 1’s. Vertical axis scale negative 2 to 3 by 1’s. Quadrilateral A B B prime A prime has coordinates A(negative 2 comma 1), B(1 comma 2), B prime(4 comma 0) and A prime (1 comma negative 1).

Reflecting a point across an axis changes the sign of one coordinate.

For example, reflecting the point AA whose coordinates are (2,-1)(2,\text-1) across the xx-axis changes the sign of the yy-coordinate, making its image the point AA’ whose coordinates are (2,1)(2,1). Reflecting the point AA across the yy-axis changes the sign of the xx-coordinate, making the image the point A’’A’’ whose coordinates are (-2,-1)(\text-2,\text-1).

3 points on a coordinate plane.
3 points on a coordinate plane. Horizontal axis scale negative 3 to 5 by 1’s. Vertical axis scale negative 2 to 2 by 1’s. The points have these coordinates: A(2 comma negative 1), A prime(2 comma 1) and A double prime (negative 2 comma negative 1).

Reflections across other lines are more complex to describe.

We don’t have the tools yet to describe rotations in terms of coordinates in general. Here is an example of a 9090^\circ rotation with center (0,0)(0,0) in a counterclockwise direction.

Point AA has coordinates (0,0)(0,0). Segment ABAB is rotated 9090^\circ counterclockwise around AA. Point BB with coordinates (2,3)(2,3) rotates to point BB’ whose coordinates are (-3,2)(\text-3,2).

Segment A B rotated on a coordinate plane, origin O.
Segment A B rotated on a coordinate plane, origin O. Horizontal axis scale negative 4 to 4 by 1’s. Vertical axis scale negative 2 to 4 by 1’s. The segments have these coordinates: A(0 comma 0), B(2 comma 3) and B prime (negative 3 comma 2). Angle B A B prime is a right angle.

Rotation or Reflection (1 problem)

One of the triangles pictured is a rotation of triangle ABCABC and one of them is a reflection.

<p>Triangle A B C reflected on a coordinate plane, origin O.</p>
Triangle A B C reflected on a coordinate plane, origin O. Horizontal axis scale negative 6 to 6 by 1’s. Vertical axis scale negative 5 to 5 by 1’s. Triangle A B C is blue and has coordinates: A(1 comma 1), B(3 comma 2) and C(2 comma 5). The green triangle has coordinates: (negative 1 comma 1), (negative 2 comma 3) and (negative 5 comma 2). The red triangle has coordinates: (1 comma negative 1), (3 comma negative 2) and (2 comma negative 5).

  1. Label the rotated image PQRPQR.
  2. Label the reflected image XYZXYZ.
Show Solution

<p>Image of sequence of transformations.</p>

Section A Check
Section A Checkpoint
Lesson 7
No Bending or Stretching

The transformations we’ve learned about so far, translations, rotations, reflections, and sequences of these motions, are all examples of rigid transformations. A rigid transformation is a move that doesn’t change measurements on any figure.

Earlier, we learned that a figure and its image have corresponding points. With a rigid transformation, figures like polygons also have corresponding sides and corresponding angles. These corresponding parts have the same measurements.

For example, triangle EFDEFD was made by reflecting triangle ABCABC across a horizontal line, then translating. Corresponding sides have the same lengths, and corresponding angles have the same measures.

Triangle A, B, C and its image after reflection and translation.

Measurements in triangle ABCABC Corresponding measurements in image EFDEFD
AB=2.24AB = 2.24 EF=2.24EF = 2.24
BC=2.83BC = 2.83 FD =2.83FD = 2.83
CA=3.00CA = 3.00 DE =3.00DE = 3.00
angle ABC=71.6ABC = 71.6^\circ angle EFD=71.6EFD= 71.6^\circ
angle BCA=45.0BCA = 45.0^\circ angle FDE=45.0FDE= 45.0^\circ
angle CAB=63.4CAB = 63.4^\circ angle DEF=63.4DEF= 63.4^\circ
Translated Trapezoid (1 problem)

Trapezoid ABCDA’B’C’D’ is the image of trapezoid ABCDABCD under a rigid transformation.

Trapezoid A B C D and its image, trapezoid A prime B prime C prime and D prime.<br>
 
Trapezoid A B C D and its image, trapezoid A prime B prime C prime and D prime. Angle A is 130 degrees, angle B is 50 degrees and angles D and C are right angles. Side A prime D prime is 6 units and side D prime C prime is 4 units.  

  1. Label all vertices on trapezoid ABCDA’B’C’D’.
  2. On both figures, label all known side lengths and angle measures.
Show Solution

<p>Transformations on quadrilateral ABCD.</p>

Lesson 10
Composing Figures

Earlier, we learned that if we apply a sequence of rigid transformations to a figure, then corresponding sides have equal length and corresponding angles have equal measure. These facts let us figure out things without having to measure them!

For example, here is triangle ABCABC.

A triangle A, B, C where the interior angle at A has measure 36 degrees.

We can reflect triangle ABCABC across side ACAC to form a new triangle:

Triangle A, B, C, with angle with measure 36 degrees at A. It has been reflected on the side A, C.

Because points AA and CC are on the line of reflection, they do not move. So the image of triangle ABCABC is ABCAB'C. We also know that:

  • Angle BACB'AC measures 3636^\circ because it is the image of angle BACBAC.
  • Segment ABAB' has the same length as segment ABAB.

When we construct figures using copies of a figure made with rigid transformations, we know that the measures of the images of segments and angles will be equal to the measures of the original segments and angles.

Identifying Side Lengths and Angle Measures (1 problem)

Two quadrilaterals, A B C D on the left and A B C E.<br>
 
Two quadrilaterals, A B C D on the left and A B C E on the right. Both have segment A C, and quadrilateral A B C E has midpoint M on A C. Quadrilateral A B C D has side A B length 2 point 7, angle B is 64 point 3 degrees and side B C is 3 point 2. Quadrilateral has  A B C E has side A B length 2 point 7, angle B is 64 point 3 degrees and side B C is 3 point 2. Point E on quadrilateral A B C E is about the same level as the midpoint M and angle B. Point D on quadrilateral A B C D is above the level of the angle B and the midpoint of segment A C.  

Here is a diagram showing triangle ABCABC and some transformations of triangle ABCABC.

On the left side of the diagram, triangle ABCABC has been reflected across line ACAC to form quadrilateral ABCDABCD. On the right side of the diagram, triangle ABCABC has been rotated 180180^\circusing midpoint MM as a center to form quadrilateral ABCEABCE.

Using what you know about rigid transformations, side lengths and angle measures, label as many side lengths and angle measures as you can in quadrilaterals ABCDABCD and ABCEABCE.

Show Solution

<p>Transformation of triangle ABC.</p>

Section B Check
Section B Checkpoint
Lesson 12
Congruent Polygons
How do we know if two figures are congruent?
  • If we copy one figure on tracing paper and move the paper so the copy covers the other figure exactly, then that suggests they are congruent.
  • If we can describe a sequence of translations, rotations, and reflections that move one figure onto the other so they match up exactly, they are congruent.
How do we know that two figures are not congruent?
  • If there is no correspondence between the figures where the parts have equal measure, that shows that the two figures are not congruent.
    • If two polygons have different sets of side lengths, they can’t be congruent.

      For example, the figure on the left has side lengths 3, 2, 1, 1, 2, 1. The figure on the right has side lengths 3, 3, 1, 2, 2, 1. There is no way to make a correspondence between them where all corresponding sides have the same length.

      Two figures on a grid. The figure on the left has side lengths 3, 2, 1, 1, 2, 1. The figure on the right has side lengths 3, 3, 1, 2, 2, 1.
    • If two polygons have the same side lengths, but not in the same order, the polygons can’t be congruent.

      For example, rectangle ABCDABCD can’t be congruent to quadrilateral EFGHEFGH. Even though they both have two sides of length 3 and two sides of length 5, they don’t correspond in the same order.

      Two figures, A B C D and E F G H.
      Two figures, A B C D and E F G H. Figure A B C D is a rectangle with side length 3 and base and top length 5. Figure E F G H has base length 5, top length is 3, left side length is 3 and right side length is 5.

    • If two polygons have the same side lengths, in the same order, but different corresponding angles, the polygons can’t be congruent.

      For example, parallelogram JKLMJKLM can’t be congruent to rectangle ABCDABCD. Even though they have the same side lengths in the same order, the angles are different. All angles in ABCDABCD are right angles. In JKLMJKLM, angles JJ and LL are less than 90 degrees and angles KK and MM are more than 90 degrees.

      Parallelogram J K L M with base and top length 5 units and sides length 3 units.

Moving to Congruence (1 problem)

Describe a sequence of reflections, rotations, and translations that shows that quadrilateral ABCDABCD is congruent to quadrilateral EFGHEFGH.

Two figures, trapezoids A B C D and E F G H on a square grid.
Two figures, trapezoids A B C D and E F G H on a square grid. Let the lower left corner be (0 comma 0), Then trapezoid A B C D has points A(1 comma 6), B(1 comma 2), C(6 comma 2) and D(2 comma 6). Trapezoid E F G H has points E(7 comma 6), F(11 comma 6), G(11 comma 1) and H(7 comma 6).

Show Solution

Sample response: Translate ABCDABCD down 1 and 5 to the right. Then reflect over line GHGH.

Section C Check
Section C Checkpoint
Lesson 14
Alternate Interior Angles

When two lines intersect, vertical angles are congruent, and adjacent angles are supplementary, so their measures sum to 180. For example, in this figure angles 1 and 3 are congruent, angles 2 and 4 are congruent, angles 1 and 4 are supplementary, and angles 2 and 3 are supplementary.

Two intersecting lines.
Two intersecting lines. Angle 1 is labeled 70 degrees. Angle 2 is labeled 110 degrees. Angle 3 is labeled 70 degrees. Angle 4 is labeled 110 degrees.

When two parallel lines are cut by another line, called a transversal, two pairs of alternate interior angles are created. (“Interior” means on the inside, or between, the two parallel lines.) For example, in this figure angles 3 and 5 are alternate interior angles and angles 4 and 6 are also alternate interior angles.

Two lines that do not intersect. A third line intersects with both lines.
Two lines that do not intersect. A third line intersects with both lines. At the first intersection, angle 1 is labeled 70 degrees. Angle 2 is labeled 110 degrees. Angle 3 is labeled 70 degrees. Angle 4 is labeled 110 degrees. At the second intersection, angle 5 is marked 70 degrees. Angle 6 is marked 110 degrees. Angle 7 is marked 70 degrees. Angle 8 is marked 110 degrees.

Alternate interior angles are equal because a 180180^\circ rotation around the midpoint of the segment that joins their vertices takes each angle to the other. Imagine a point MM halfway between the two intersections. Can you see how rotating 180180^\circ about MM takes angle 3 to angle 5?

Using what we know about vertical angles, adjacent angles, and alternate interior angles, we can find the measures of any of the eight angles created by a transversal if we know just one of them. For example, starting with the fact that angle 1 is 7070^\circ we use vertical angles to see that angle 3 is 7070^\circ, then we use alternate interior angles to see that angle 5 is 7070^\circ, then we use the fact that angle 5 is supplementary to angle 8 to see that angle 8 is  110110^\circ since 18070=110180 -70 = 110. It turns out that there are only two different measures. In this example, angles 1, 3, 5, and 7 measure 7070^\circ, and angles 2, 4, 6, and 8 measure 110110^\circ.

All the Rest (1 problem)

The diagram shows two parallel lines cut by a transversal. One angle measure is shown.

Two lines that do not intersect. A third line intersects with both lines.
Two lines that do not intersect. A third line intersects with both lines. At the first intersection, angles are marked in clockwise order as a degrees, b, degrees, c degrees, and 54 degrees. At the second intersection, angles are marked in clockwise order as e degrees, f degrees, g degrees, and d degrees.

Find the values of aa, bb, cc, dd, ee, ff, and gg.

Show Solution

aa: 126126bb: 5454, cc: 126126, dd: 5454, ee: 126126, ff: 5454, gg: 126126

Lesson 15
Adding the Angles in a Triangle

A 180180^\circ angle is called a straight angle because when it is made with two rays, they point in opposite directions and form a straight line.

A line with point marked. Angle is marked 180 degrees. 

If we experiment with angles in a triangle, we find that the sum of the measures of the three angles in each triangle is 180180^\circ— the same as a straight angle!

Through experimentation we find:

  • If we add the three angles of a triangle physically by cutting them off and lining up the vertices and sides, then the three angles form a straight angle.

  • If we have a line and two rays that form three angles added to make a straight angle, then there is a triangle with these three angles.

    A triangle. The angles are colored blue, red, and green. A line with two rays forming three angles. The angles are colored blue, red, and green.

Three Angles (1 problem)

Tyler has 3 right angles. Can he use them to make a triangle? Explain your reasoning.

Show Solution

No. Sample reasoning: 3 right angles sums to more than 180 degrees, since 390=2703\boldcdot90=270.

Section D Check
Section D Checkpoint
Unit 1 Assessment
End-of-Unit Assessment