Equations can be solved in many ways. In this lesson, we focused on equations with a specific structure, and two specific ways to solve them.
Suppose we are trying to solve the equation 54(x+27)=16. Two useful approaches are:
In order to decide which approach is better, we can look at the numbers and think about which would be easier to compute. We notice that 54⋅27 will be hard, because 27 isn't divisible by 5. So, distributing the 54 is not the best method. But 16÷ 54 gives us 16⋅45, and 16 is divisible by 4. So, dividing each side by 54 is a good choice.
54(x+27)45⋅54(x+27)x+27x=16=16⋅45=20=-7
Sometimes the calculations are simpler if we first use the distributive property. Let's look at the equation 100(x+0.06)=21. If we first divide each side by 100, we get 10021 or 0.21 on the right side of the equation. But if we use the distributive property first, we get an equation that only contains whole numbers.
100(x+0.06)100x+6100xx=21=21=15=10015