A Different Kind of Change

Student Summary

In this lesson, we looked at the relationship between the side lengths and the area of a rectangle when the perimeter is unchanged.

If a rectangle has a perimeter of 40 inches, we can represent some of the possible lengths and widths as shown in the table.

We know that twice the length and twice the width must equal 40, which means that the length plus width must equal 20, or +w=20\ell + w = 20.

length (inches) width (inches)
2 18
5 15
10 10
12 8
15 5

To find the width given a length \ell, we can write: w=20w= 20- \ell.

The relationship between the length and the width is linear. If we plot the points from the table representing the length and the width, they form a line.

<p>Points plotted. Horizontal axis, length in inches, 0 to 24 by 4’s. Vertical axis, width in inches, 0 to 40 by 10’s. Points at 2 comma 18, 5 comma 15, 10 comma 10, 12 comma 8, 15 comma 5.</p>

What about the relationship between the side lengths and the area of rectangles with a perimeter of 40 inches?

Here are some possible areas of different rectangles that have a perimeter of 40 inches.

length (inches) width (inches) area (square inches)
2 18 36
5 15 75
10 10 100
12 8 96
15 5 75

Here is a graph of the lengths and areas from the table:

<p>Points plotted. Horizontal axis, length in inches, 0 to 24 by 4’s. Vertical axis, area in square inches, 0 to 125 by 25’s. Points at 2 comma 36, 5 comma 75, 10 comma 100, 12 comma 96, 15 comma 75.</p>

Notice that, initially, as the length of the rectangle increases (for example, from 5 to 10 inches), the area also increases (from 75 to 100 square inches). Later, however, as the length increases (for example, from 12 to 15), the area decreases (from 96 to 75).

We have not studied relationships like this yet and will investigate them further in this unit.

Visual / Anchor Chart

Standards

Building On
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Addressing
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Building Toward
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