Completing the Square (Part 1)

Student Summary

Turning an expression into a perfect square can be a good way to solve a quadratic equation. Suppose we wanted to solve x214x+10=-30x^2 - 14x +10 = \text-30.

The expression on the left, x214x+10x^2 - 14x +10, is not a perfect square, but x214x+49x^2 - 14x + 49 is a perfect square. Let’s transform that side of the equation into a perfect square (while keeping the equality of the two sides).

  • One helpful way to start is by first moving the constant that is not a perfect square out of the way. Let’s subtract 10 from each side:​​​​​​

x214x+1010=-3010x214x=-40\displaystyle \begin{aligned} x^2 - 14x +10 - 10 &= \text-30 - 10\\ x^2 - 14x &= \text-40 \end{aligned}

  • And then add 49 to each side:​​​​​​

x214x+49=-40+49x214x+49=9\displaystyle \begin{aligned} x^2 - 14x +49 &= \text-40 +49\\ x^2 - 14x+49 &= 9 \end{aligned}

  • The left side is now a perfect square because it’s equivalent to (x7)(x7)(x-7)(x-7) or (x7)2(x-7)^2. Let’s rewrite it:

(x7)2=9\displaystyle (x-7)^2=9

  • If a number squared is 9, the number has to be 3 or -3. Solve to finish up:​​​​​​

x7=3orx7=-3x=10orx=4\displaystyle \begin{aligned} x-7=3 \quad & \text{or} \quad x-7=\text-3\\ x=10 \quad & \text{or} \quad x=4 \end{aligned}

This method of solving quadratic equations is called completing the square. In general, perfect squares in standard form look like x2+bx+(b2)2x^2 + bx + \left(\frac{b}{2} \right)^2, so to complete the square, take half of the coefficient of the linear term and square it.

In the example, half of -14 is -7, and (-7)2(\text-7)^2 is 49. We wanted to make the left side x214x+49.x^2 - 14x + 49. To keep the equation true and maintain equality of the two sides of the equation, we added 49 to each side.

Visual / Anchor Chart

Standards

Addressing
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